2x^2-36x-270=0

Solution for 2x^2-36x-270=0 equation:

2x^2-36x-270=0

a = 2; b = -36; c = -270;
Δ = b2-4ac
Δ = -362-4·2·(-270)
Δ = 3456
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3456}=\sqrt{576*6}=\sqrt{576}*\sqrt{6}=24\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-24\sqrt{6}}{2*2}=\frac{36-24\sqrt{6}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+24\sqrt{6}}{2*2}=\frac{36+24\sqrt{6}}{4}
$